¿Cómo compartir una imagen en Instagram en iOS?

Mi cliente quiere compartir una imagen en Instagram, Twitter, Facebook.

He hecho Twitter y Facebook, pero no encontré ninguna API ni nada en Internet para compartir imágenes en Instagram. ¿Es posible compartir imágenes en Instagram? ¿Si es así, entonces cómo?

Cuando reviso el sitio para desarrolladores de Instagram, he encontrado las Bibliotecas de Ruby on Rails y Python. Pero no hay documentación de iOS Sdk

Tengo token de instagram según instagram.com/developer, pero ahora no sé qué hacer con el siguiente paso para compartir con la imagen de Instagram.

Finalmente obtuve la respuesta. no puedes publicar una imagen directamente en instagram. Debe redirigir su imagen con UIDocumentInteractionController.

@property (nonatomic, retain) UIDocumentInteractionController *dic; CGRect rect = CGRectMake(0 ,0 , 0, 0); UIGraphicsBeginImageContextWithOptions(self.view.bounds.size, self.view.opaque, 0.0); [self.view.layer renderInContext:UIGraphicsGetCurrentContext()]; UIGraphicsEndImageContext(); NSString *jpgPath = [NSHomeDirectory() stringByAppendingPathComponent:@"Documents/test.igo"]; NSURL *igImageHookFile = [[NSURL alloc] initWithString:[[NSString alloc] initWithFormat:@"file://%@", jpgPath]]; self.dic.UTI = @"com.instagram.photo"; self.dic = [self setupControllerWithURL:igImageHookFile usingDelegate:self]; self.dic=[UIDocumentInteractionController interactionControllerWithURL:igImageHookFile]; [self.dic presentOpenInMenuFromRect: rect inView: self.view animated: YES ]; - (UIDocumentInteractionController *) setupControllerWithURL: (NSURL*) fileURL usingDelegate: (id ) interactionDelegate { UIDocumentInteractionController *interactionController = [UIDocumentInteractionController interactionControllerWithURL: fileURL]; interactionController.delegate = interactionDelegate; return interactionController; } 

NOTA: una vez que redirigir a la aplicación de Instagram no puede volver a su aplicación. debes volver a abrir tu aplicación

Descargar fuente desde aquí

Aquí hay un código completo probado para Subir imagen + texto de subtítulos a Instagram …

archivo in.h

 //Instagram @property (nonatomic, retain) UIDocumentInteractionController *documentController; -(void)instaGramWallPost { NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"]; if([[UIApplication sharedApplication] canOpenURL:instagramURL]) //check for App is install or not { NSData *imageData = UIImagePNGRepresentation(imge); //convert image into .png format. NSFileManager *fileManager = [NSFileManager defaultManager];//create instance of NSFileManager NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); //create an array and store result of our search for the documents directory in it NSString *documentsDirectory = [paths objectAtIndex:0]; //create NSString object, that holds our exact path to the documents directory NSString *fullPath = [documentsDirectory stringByAppendingPathComponent:[NSString stringWithFormat:@"insta.igo"]]; //add our image to the path [fileManager createFileAtPath:fullPath contents:imageData attributes:nil]; //finally save the path (image) NSLog(@"image saved"); CGRect rect = CGRectMake(0 ,0 , 0, 0); UIGraphicsBeginImageContextWithOptions(self.view.bounds.size, self.view.opaque, 0.0); [self.view.layer renderInContext:UIGraphicsGetCurrentContext()]; UIGraphicsEndImageContext(); NSString *fileNameToSave = [NSString stringWithFormat:@"Documents/insta.igo"]; NSString *jpgPath = [NSHomeDirectory() stringByAppendingPathComponent:fileNameToSave]; NSLog(@"jpg path %@",jpgPath); NSString *newJpgPath = [NSString stringWithFormat:@"file://%@",jpgPath]; NSLog(@"with File path %@",newJpgPath); NSURL *igImageHookFile = [[NSURL alloc]initFileURLWithPath:newJpgPath]; NSLog(@"url Path %@",igImageHookFile); self.documentController.UTI = @"com.instagram.exclusivegram"; self.documentController = [self setupControllerWithURL:igImageHookFile usingDelegate:self]; self.documentController=[UIDocumentInteractionController interactionControllerWithURL:igImageHookFile]; NSString *caption = @"#Your Text"; //settext as Default Caption self.documentController.annotation=[NSDictionary dictionaryWithObjectsAndKeys:[NSString stringWithFormat:@"%@",caption],@"InstagramCaption", nil]; [self.documentController presentOpenInMenuFromRect:rect inView: self.view animated:YES]; } else { NSLog (@"Instagram not found"); } } - (UIDocumentInteractionController *) setupControllerWithURL: (NSURL*) fileURL usingDelegate: (id ) interactionDelegate { NSLog(@"file url %@",fileURL); UIDocumentInteractionController *interactionController = [UIDocumentInteractionController interactionControllerWithURL: fileURL]; interactionController.delegate = interactionDelegate; return interactionController; } 

O

 -(void)instaGramWallPost { NSURL *myURL = [NSURL URLWithString:@"Your image url"]; NSData * imageData = [[NSData alloc] initWithContentsOfURL:myURL]; UIImage *imgShare = [[UIImage alloc] initWithData:imageData]; NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"]; if([[UIApplication sharedApplication] canOpenURL:instagramURL]) //check for App is install or not { UIImage *imageToUse = imgShare; NSString *documentDirectory=[NSHomeDirectory() stringByAppendingPathComponent:@"Documents"]; NSString *saveImagePath=[documentDirectory stringByAppendingPathComponent:@"Image.igo"]; NSData *imageData=UIImagePNGRepresentation(imageToUse); [imageData writeToFile:saveImagePath atomically:YES]; NSURL *imageURL=[NSURL fileURLWithPath:saveImagePath]; self.documentController=[[UIDocumentInteractionController alloc]init]; self.documentController = [UIDocumentInteractionController interactionControllerWithURL:imageURL]; self.documentController.delegate = self; self.documentController.annotation = [NSDictionary dictionaryWithObjectsAndKeys:[NSString stringWithFormat:@"Testing"], @"InstagramCaption", nil]; self.documentController.UTI = @"com.instagram.exclusivegram"; UIViewController *vc = [UIApplication sharedApplication].keyWindow.rootViewController; [self.documentController presentOpenInMenuFromRect:CGRectMake(1, 1, 1, 1) inView:vc.view animated:YES]; } else { DisplayAlertWithTitle(@"Instagram not found", @"") } } 

y escribe esto en .plist

 LSApplicationQueriesSchemes  instagram  

Espero que esta respuesta resuelva tu consulta. Esto abrirá directamente la carpeta de la biblioteca en Instagram en lugar de la cámara.

 NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"]; if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) { NSURL *videoFilePath = [NSURL URLWithString:[NSString stringWithFormat:@"%@",[request downloadDestinationPath]]]; // Your local path to the video NSString *caption = @"Some Preloaded Caption"; ALAssetsLibrary *library = [[ALAssetsLibrary alloc] init]; [library writeVideoAtPathToSavedPhotosAlbum:videoFilePath completionBlock:^(NSURL *assetURL, NSError *error) { NSString *escapedString = [self urlencodedString:videoFilePath.absoluteString]; NSString *escapedCaption = [self urlencodedString:caption]; NSURL *instagramURL = [NSURL URLWithString:[NSString stringWithFormat:@"instagram://library?AssetPath=%@&InstagramCaption=%@",escapedString,escapedCaption]]; if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) { [[UIApplication sharedApplication] openURL:instagramURL]; } }]; 

Puede usar uno de los esquemas de url provistos por Instagram

enter image description here

  1. Archivo oficial de Instagram aquí

  2. Compartir con UIDocumentInteractionController

     final class InstagramPublisher : NSObject { private var documentsController:UIDocumentInteractionController = UIDocumentInteractionController() func postImage(image: UIImage, view: UIView, result:((Bool)->Void)? = nil) { guard let instagramURL = NSURL(string: "instagram://app") else { if let result = result { result(false) } return } if UIApplication.sharedApplication().canOpenURL(instagramURL) { let jpgPath = (NSTemporaryDirectory() as NSString).stringByAppendingPathComponent("instagrammFotoToShareName.igo") if let image = UIImageJPEGRepresentation(image, 1.0) { image.writeToFile(jpgPath, atomically: true) let fileURL = NSURL.fileURLWithPath(jpgPath) documentsController.URL = fileURL documentsController.UTI = "com.instagram.exclusivegram" documentsController.presentOpenInMenuFromRect(view.bounds, inView: view, animated: true) if let result = result { result(true) } } else if let result = result { result(false) } } else { if let result = result { result(false) } } } } 
  3. Compartir con redirigir directamente

     import Photos final class InstagramPublisher : NSObject { func postImage(image: UIImage, result:((Bool)->Void)? = nil) { guard let instagramURL = NSURL(string: "instagram://app") else { if let result = result { result(false) } return } let image = image.scaleImageWithAspectToWidth(640) do { try PHPhotoLibrary.sharedPhotoLibrary().performChangesAndWait { let request = PHAssetChangeRequest.creationRequestForAssetFromImage(image) let assetID = request.placeholderForCreatedAsset?.localIdentifier ?? "" let shareURL = "instagram://library?LocalIdentifier=" + assetID if UIApplication.sharedApplication().canOpenURL(instagramURL) { if let urlForRedirect = NSURL(string: shareURL) { UIApplication.sharedApplication().openURL(urlForRedirect) } } } } catch { if let result = result { result(false) } } } } 
  4. extensión para cambiar el tamaño de la foto al tamaño recomendado

     import UIKit extension UIImage { // MARK: - UIImage+Resize func scaleImageWithAspectToWidth(toWidth:CGFloat) -> UIImage { let oldWidth:CGFloat = size.width let scaleFactor:CGFloat = toWidth / oldWidth let newHeight = self.size.height * scaleFactor let newWidth = oldWidth * scaleFactor; UIGraphicsBeginImageContext(CGSizeMake(newWidth, newHeight)) drawInRect(CGRectMake(0, 0, newWidth, newHeight)) let newImage = UIGraphicsGetImageFromCurrentImageContext() UIGraphicsEndImageContext() return newImage } } 
  5. No olvide agregar el esquema requerido en plist

  LSApplicationQueriesSchemes  instagram  

Para iOS 6 y versiones superiores, puedes usar esta UIActivity para subir imágenes a Instagram que tiene el mismo flujo de trabajo con iOS hooks pero simplifica el desarrollo:

https://github.com/coryalder/DMActivityInstagram

si no quieres usar UIDocumentInteractionController

 import Photos ... func postImageToInstagram(image: UIImage) { UIImageWriteToSavedPhotosAlbum(image, self, #selector(SocialShare.image(_:didFinishSavingWithError:contextInfo:)), nil) } func image(image: UIImage, didFinishSavingWithError error: NSError?, contextInfo:UnsafePointer) { if error != nil { print(error) } let fetchOptions = PHFetchOptions() fetchOptions.sortDescriptors = [NSSortDescriptor(key: "creationDate", ascending: false)] let fetchResult = PHAsset.fetchAssetsWithMediaType(.Image, options: fetchOptions) if let lastAsset = fetchResult.firstObject as? PHAsset { let localIdentifier = lastAsset.localIdentifier let u = "instagram://library?LocalIdentifier=" + localIdentifier let url = NSURL(string: u)! if UIApplication.sharedApplication().canOpenURL(url) { UIApplication.sharedApplication().openURL(NSURL(string: u)!) } else { let alertController = UIAlertController(title: "Error", message: "Instagram is not installed", preferredStyle: .Alert) alertController.addAction(UIAlertAction(title: "OK", style: .Default, handler: nil)) self.presentViewController(alertController, animated: true, completion: nil) } } } 

esta es la respuesta correcta que implemento con detalle. En archivo .h

  UIImageView *imageMain; @property (nonatomic, strong) UIDocumentInteractionController *documentController; 

archivo in.m solo escribe

  NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"]; if([[UIApplication sharedApplication] canOpenURL:instagramURL]) { CGFloat cropVal = (imageMain.image.size.height > imageMain.image.size.width ? imageMain.image.size.width : imageMain.image.size.height); cropVal *= [imageMain.image scale]; CGRect cropRect = (CGRect){.size.height = cropVal, .size.width = cropVal}; CGImageRef imageRef = CGImageCreateWithImageInRect([imageMain.image CGImage], cropRect); NSData *imageData = UIImageJPEGRepresentation([UIImage imageWithCGImage:imageRef], 1.0); CGImageRelease(imageRef); NSString *writePath = [NSTemporaryDirectory() stringByAppendingPathComponent:@"instagram.igo"]; if (![imageData writeToFile:writePath atomically:YES]) { // failure NSLog(@"image save failed to path %@", writePath); return; } else { // success. } // send it to instagram. NSURL *fileURL = [NSURL fileURLWithPath:writePath]; self.documentController = [UIDocumentInteractionController interactionControllerWithURL:fileURL]; self.documentController.delegate = self; [self.documentController setUTI:@"com.instagram.exclusivegram"]; [self.documentController setAnnotation:@{@"InstagramCaption" : @"We are making fun"}]; [self.documentController presentOpenInMenuFromRect:CGRectMake(0, 0, 320, 480) inView:self.view animated:YES]; } else { NSLog (@"Instagram not found"); } 

Seguro que obtendrás un resultado. Por ejemplo, verá popover desde abajo con imagen de instagram. Haga clic en él y diviértase.

Intenté esto en mi aplicación y está funcionando perfectamente (Swift)

 import Foundation import UIKit class InstagramManager: NSObject, UIDocumentInteractionControllerDelegate { private let kInstagramURL = "instagram://" private let kUTI = "com.instagram.exclusivegram" private let kfileNameExtension = "instagram.igo" private let kAlertViewTitle = "Error" private let kAlertViewMessage = "Please install the Instagram application" var documentInteractionController = UIDocumentInteractionController() // singleton manager class var sharedManager: InstagramManager { struct Singleton { static let instance = InstagramManager() } return Singleton.instance } func postImageToInstagramWithCaption(imageInstagram: UIImage, instagramCaption: String, view: UIView) { // called to post image with caption to the instagram application let instagramURL = NSURL(string: kInstagramURL) if UIApplication.sharedApplication().canOpenURL(instagramURL!) { let jpgPath = (NSTemporaryDirectory() as NSString).stringByAppendingPathComponent(kfileNameExtension) UIImageJPEGRepresentation(imageInstagram, 1.0)!.writeToFile(jpgPath, atomically: true) let rect = CGRectMake(0,0,612,612) let fileURL = NSURL.fileURLWithPath(jpgPath) documentInteractionController.URL = fileURL documentInteractionController.delegate = self documentInteractionController.UTI = kUTI // adding caption for the image documentInteractionController.annotation = ["InstagramCaption": instagramCaption] documentInteractionController.presentOpenInMenuFromRect(rect, inView: view, animated: true) } else { // alert displayed when the instagram application is not available in the device UIAlertView(title: kAlertViewTitle, message: kAlertViewMessage, delegate:nil, cancelButtonTitle:"Ok").show() } } } func sendToInstagram(){ let image = postImage InstagramManager.sharedManager.postImageToInstagramWithCaption(image!, instagramCaption: "\(description)", view: self.view) } 

Aquí está la respuesta correcta. no puedes publicar una imagen directamente en Instagram. Debes redirigir a Instagram usando UIDocumentInteractionController …

 NSString* imagePath = [NSString stringWithFormat:@"%@/instagramShare.igo", [NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) lastObject]]; [[NSFileManager defaultManager] removeItemAtPath:imagePath error:nil]; UIImage *instagramImage = [UIImage imageNamed:@"imagename you want to share"]; [UIImagePNGRepresentation(instagramImage) writeToFile:imagePath atomically:YES]; NSLog(@"Image Size >>> %@", NSStringFromCGSize(instagramImage.size)); self.dic=[UIDocumentInteractionController interactionControllerWithURL:[NSURL fileURLWithPath:imagePath]]; self.dic.delegate = self; self.dic.UTI = @"com.instagram.exclusivegram"; [self.dic presentOpenInMenuFromRect: self.view.frame inView:self.view animated:YES ]; 

}

NOTA: una vez que redirigir a la aplicación de Instagram no puede volver a su aplicación. debes volver a abrir tu aplicación

 - (void) shareImageWithInstagram { NSURL *instagramURL = [NSURL URLWithString:@"instagram://"]; if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) { UICachedFileMgr* mgr = _gCachedManger; UIImage* photoImage = [mgr imageWithUrl:_imageView.image]; NSData* imageData = UIImagePNGRepresentation(photoImage); NSString* captionString = [NSString stringWithFormat:@"ANY_TAG",]; NSString* imagePath = [UIUtils documentDirectoryWithSubpath:@"image.igo"]; [imageData writeToFile:imagePath atomically:NO]; NSURL* fileURL = [NSURL fileURLWithPath:[NSString stringWithFormat:@"file://%@",imagePath]]; self.docFile = [[self setupControllerWithURL:fileURL usingDelegate:self]retain]; self.docFile.annotation = [NSDictionary dictionaryWithObject: captionString forKey:@"InstagramCaption"]; self.docFile.UTI = @"com.instagram.photo"; // OPEN THE HOOK [self.docFile presentOpenInMenuFromRect:self.view.frame inView:self.view animated:YES]; } else { [UIUtils messageAlert:@"Instagram not installed in this device!\nTo share image please install instagram." title:nil delegate:nil]; } } 

Intenté esto en mi aplicación y definitivamente funcionará

En cuanto a mí, la mejor y la manera más fácil descrita aquí Compartir fotos en Instagram desde mi aplicación iOS

Debe guardar la imagen en el dispositivo usando el formato .igo, luego use “UIDocumentInteractionController” para enviar la aplicación local de Instagram. No olvides configurar “UIDocumentInteractionControllerDelegate”

Mi consejo es agregar algo como:

 NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"]; if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) {  } 
 NSURL *instagramURL = [NSURL URLWithString:@"instagram://app"]; if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) { NSString *jpgPath = [NSHomeDirectory() stringByAppendingPathComponent:[NSString stringWithFormat:@"Documents/Insta_Images/%@",@"shareImage.png"]]; NSURL *igImageHookFile = [[NSURL alloc] initWithString:[[NSString alloc] initWithFormat:@"file://%@", jpgPath]]; docController.UTI = @"com.instagram.photo"; docController = [self setupControllerWithURL:igImageHookFile usingDelegate:self]; docController =[UIDocumentInteractionController interactionControllerWithURL:igImageHookFile]; docController.delegate=self; [docController presentOpenInMenuFromRect:CGRectMake(0 ,0 , 612, 612) inView:self.view animated:YES]; 

Puede hacerlo sin utilizar el UIDocumentInteractionController e ir directamente a Instagram con estos 3 métodos:

Funciona igual que todas las otras aplicaciones famosas. El código está escrito en Objective c, por lo que puede traducirlo a swift si lo desea. Lo que debe hacer es guardar su imagen en el dispositivo y usar un URLScheme

agregue esto dentro de su archivo .m

 #import  

Primero debes guardar tu UIImage en el dispositivo con este método:

 -(void)savePostsPhotoBeforeSharing { UIImageWriteToSavedPhotosAlbum([UIImage imageNamed:@"image_file_name.jpg"], self, @selector(image:didFinishSavingWithError:contextInfo:), NULL); } 

Este método es la callback para guardar la imagen en su dispositivo:

 - (void)image:(UIImage *)image didFinishSavingWithError:(NSError *)error contextInfo: (void *) contextInfo; { [self sharePostOnInstagram]; } 

Después de guardar la imagen en el dispositivo, debe consultar la imagen que acaba de guardar y obtenerla como un PHAsset

 -(void)sharePostOnInstagram { PHFetchOptions *fetchOptions = [PHFetchOptions new]; fetchOptions.sortDescriptors = @[[NSSortDescriptor sortDescriptorWithKey:@"creationDate" ascending:NO],]; __block PHAsset *assetToShare; PHFetchResult *result = [PHAsset fetchAssetsWithMediaType:PHAssetMediaTypeImage options:fetchOptions]; [result enumerateObjectsUsingBlock:^(PHAsset *asset, NSUInteger idx, BOOL *stop) { assetToShare = asset; }]; if([assetToShare isKindOfClass:[PHAsset class]]) { NSString *localIdentifier = assetToShare.localIdentifier; NSString *urlString = [NSString stringWithFormat:@"instagram://library?LocalIdentifier=%@",localIdentifier]; NSURL *instagramURL = [NSURL URLWithString:urlString]; if ([[UIApplication sharedApplication] canOpenURL: instagramURL]) { [[UIApplication sharedApplication] openURL: instagramURL]; } else { // can not share with whats app NSLog(@"No instagram installed"); } } } 

Y no olvides poner esto en tu info.plist bajo LSApplicationQueriesSchemes

 instagram 

Usé este código:

  NSString* filePathStr = [[NSBundle mainBundle] pathForResource:@"UMS_social_demo" ofType:@"png"]; NSURL* fileUrl = [NSURL fileURLWithPath:filePathStr]; NSString *jpgPath = [NSHomeDirectory() stringByAppendingPathComponent:@"Documents/test.igo"]; [[NSData dataWithContentsOfURL:fileUrl] writeToFile:jpgPath atomically:YES]; NSURL* documentURL = [NSURL URLWithString:[NSString stringWithFormat:@"file://%@", jpgPath]]; UIDocumentInteractionController *interactionController = [UIDocumentInteractionController interactionControllerWithURL: documentURL]; self.interactionController = interactionController; interactionController.delegate = self; interactionController.UTI = @"com.instagram.photo"; CGRect rect = CGRectMake(0 ,0 , 0, 0); [interactionController presentOpenInMenuFromRect:rect inView:self.view animated:YES]; 
 -(void)shareOnInstagram { CGRect rect = CGRectMake(self.view.frame.size.width*0.375 ,self.view.frame.size.height/2 , 0, 0); NSString * saveImagePath = [NSHomeDirectory() stringByAppendingPathComponent:@"Documents/ShareInstragramImage.igo"]; [UIImagePNGRepresentation(_image) writeToFile:saveImagePath atomically:YES]; NSURL *igImageHookFile = [[NSURL alloc] initWithString:[[NSString alloc] initWithFormat:@"file://%@", saveImagePath]]; self.documentController=[UIDocumentInteractionController interactionControllerWithURL:igImageHookFile]; self.documentController.UTI = @"com.instagram.exclusivegram"; self.documentController = [self setupControllerWithURL:igImageHookFile usingDelegate:self]; [self.documentController presentOpenInMenuFromRect: rect inView: self.view animated: YES ]; } -(UIDocumentInteractionController *) setupControllerWithURL: (NSURL*) fileURL usingDelegate: (id ) interactionDelegate { UIDocumentInteractionController *interactionController = [UIDocumentInteractionController interactionControllerWithURL: fileURL]; interactionController.delegate = interactionDelegate; return interactionController; } 

Me di cuenta de que si colocas la URL apunta a la imagen en activityItems lugar de UIImage , el elemento de actividad Copy to Instagram aparece a sí mismo, y no tienes que hacer nada más. Tenga en cuenta que los objetos String dentro de activityItems se descartarán y no hay forma de rellenar los subtítulos en Instagram. Si aún desea indicarle al usuario que publique un título en particular, deberá crear una actividad personalizada donde copie ese texto al portapapeles y le informe al usuario, como en este artículo .

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