Android HttpPost: cómo obtener el resultado

He intentado durante mucho tiempo enviar una solicitud de HttpPost y recuperar la respuesta, pero aunque pude establecer una conexión, aún no sé cómo obtener el mensaje de cadena que devuelve la solicitud-respuesta.

HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://www.myurl.com/app/page.php"); // Add your data List  nameValuePairs = new ArrayList  (5); nameValuePairs.add(new BasicNameValuePair("type", "20")); nameValuePairs.add(new BasicNameValuePair("mob", "919895865899")); nameValuePairs.add(new BasicNameValuePair("pack", "0")); nameValuePairs.add(new BasicNameValuePair("exchk", "1")); try { httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); Log.d("myapp", "works till here. 2"); try { HttpResponse response = httpclient.execute(httppost); Log.d("myapp", "response " + response.getEntity()); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } catch (UnsupportedEncodingException e) { e.printStackTrace(); } 

Lo siento, sueno muy ingenuo porque soy nuevo en Java. Por favor, ayúdame.

Intenta usar EntityUtil en tu respuesta:

 String responseBody = EntityUtils.toString(response.getEntity()); 
  URL url; url = new URL("http://www.url.com/app.php"); URLConnection connection; connection = url.openConnection(); HttpURLConnection httppost = (HttpURLConnection) connection; httppost.setDoInput(true); httppost.setDoOutput(true); httppost.setRequestMethod("POST"); httppost.setRequestProperty("User-Agent", "Tranz-Version-t1.914"); httppost.setRequestProperty("Accept_Language", "en-US"); httppost.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); DataOutputStream dos = new DataOutputStream(httppost.getOutputStream()); dos.write(b); // bytes[] b of post data String reply; InputStream in = httppost.getInputStream(); StringBuffer sb = new StringBuffer(); try { int chr; while ((chr = in.read()) != -1) { sb.append((char) chr); } reply = sb.toString(); } finally { in.close(); } 

Este fragmento de código funciona. Lo obtuve después de la búsqueda, pero desde un código J2ME.

Puede invocar el método de ejecución con un ResponseHandler. Aquí hay un ejemplo:

 ResponseHandler responseHandler = new BasicResponseHandler(); String response = httpClient.execute(httppost, responseHandler); 

Puedes hacer esto de esta manera

  public class MyHttpPostProjectActivity extends Activity implements OnClickListener { private EditText usernameEditText; private EditText passwordEditText; private Button sendPostReqButton; private Button clearButton; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.login); usernameEditText = (EditText) findViewById(R.id.login_username_editText); passwordEditText = (EditText) findViewById(R.id.login_password_editText); sendPostReqButton = (Button) findViewById(R.id.login_sendPostReq_button); sendPostReqButton.setOnClickListener(this); clearButton = (Button) findViewById(R.id.login_clear_button); clearButton.setOnClickListener(this); } @Override public void onClick(View v) { if(v.getId() == R.id.login_clear_button){ usernameEditText.setText(""); passwordEditText.setText(""); passwordEditText.setCursorVisible(false); passwordEditText.setFocusable(false); usernameEditText.setCursorVisible(true); passwordEditText.setFocusable(true); }else if(v.getId() == R.id.login_sendPostReq_button){ String givenUsername = usernameEditText.getEditableText().toString(); String givenPassword = passwordEditText.getEditableText().toString(); System.out.println("Given username :" + givenUsername + " Given password :" + givenPassword); sendPostRequest(givenUsername, givenPassword); } } private void sendPostRequest(String givenUsername, String givenPassword) { class SendPostReqAsyncTask extends AsyncTask{ @Override protected String doInBackground(String... params) { String paramUsername = params[0]; String paramPassword = params[1]; System.out.println("*** doInBackground ** paramUsername " + paramUsername + " paramPassword :" + paramPassword); HttpClient httpClient = new DefaultHttpClient(); // In a POST request, we don't pass the values in the URL. //Therefore we use only the web page URL as the parameter of the HttpPost argument HttpPost httpPost = new HttpPost("http://www.nirmana.lk/hec/android/postLogin.php"); // Because we are not passing values over the URL, we should have a mechanism to pass the values that can be //uniquely separate by the other end. //To achieve that we use BasicNameValuePair //Things we need to pass with the POST request BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair("paramUsername", paramUsername); BasicNameValuePair passwordBasicNameValuePAir = new BasicNameValuePair("paramPassword", paramPassword); // We add the content that we want to pass with the POST request to as name-value pairs //Now we put those sending details to an ArrayList with type safe of NameValuePair List nameValuePairList = new ArrayList(); nameValuePairList.add(usernameBasicNameValuePair); nameValuePairList.add(passwordBasicNameValuePAir); try { // UrlEncodedFormEntity is an entity composed of a list of url-encoded pairs. //This is typically useful while sending an HTTP POST request. UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(nameValuePairList); // setEntity() hands the entity (here it is urlEncodedFormEntity) to the request. httpPost.setEntity(urlEncodedFormEntity); try { // HttpResponse is an interface just like HttpPost. //Therefore we can't initialize them HttpResponse httpResponse = httpClient.execute(httpPost); // According to the JAVA API, InputStream constructor do nothing. //So we can't initialize InputStream although it is not an interface InputStream inputStream = httpResponse.getEntity().getContent(); InputStreamReader inputStreamReader = new InputStreamReader(inputStream); BufferedReader bufferedReader = new BufferedReader(inputStreamReader); StringBuilder stringBuilder = new StringBuilder(); String bufferedStrChunk = null; while((bufferedStrChunk = bufferedReader.readLine()) != null){ stringBuilder.append(bufferedStrChunk); } return stringBuilder.toString(); } catch (ClientProtocolException cpe) { System.out.println("First Exception caz of HttpResponese :" + cpe); cpe.printStackTrace(); } catch (IOException ioe) { System.out.println("Second Exception caz of HttpResponse :" + ioe); ioe.printStackTrace(); } } catch (UnsupportedEncodingException uee) { System.out.println("An Exception given because of UrlEncodedFormEntity argument :" + uee); uee.printStackTrace(); } return null; } @Override protected void onPostExecute(String result) { super.onPostExecute(result); if(result.equals("working")){ Toast.makeText(getApplicationContext(), "HTTP POST is working...", Toast.LENGTH_LONG).show(); }else{ Toast.makeText(getApplicationContext(), "Invalid POST req...", Toast.LENGTH_LONG).show(); } } } SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask(); sendPostReqAsyncTask.execute(givenUsername, givenPassword); } 

}

Prueba esto, parece ser el más compacto. Aunque en el mundo real, necesitaría usar una solicitud asincrónica para que el dispositivo no se bloquee mientras se recupera la página solicitada.

http://www.softwarepassion.com/android-series-get-post-and-multipart-post-requests/

Deberías intentar usar HttpGet en lugar de HttpPost. Tuve un problema similar y eso lo resolvió.